Win a $250 Mall of America gift card and a 3-night hotel stay in Bloomington
Bloomington Minnesota Travel & Tourism is hosting a 2026 Valentine’s Day Giveaway. This opportunity invites participants to win a romantic getaway that includes a three-night stay for two at the Sheraton Bloomington Hotel and Lela Restaurant, alongside a $200 Mall of America gift card valid at various stores, restaurants, and attractions.
How to Enter
The giveaway is set to begin on January 8, 2026, at 12:00 a.m. Central Time and will conclude on February 11, 2026, at 11:59 p.m. Central Time. Eligible participants must be at least 21 years old and reside in the United States or Canada, with the exception of Quebec. To enter, individuals are required to complete an online entry form on the official giveaway website, providing basic contact details and responding to a hotel-related question. It is important to note that only one entry per person per day will be allowed.
A winner will be randomly chosen around February 12, 2026, and notified via email. Those selected must meet certain verification requirements, which include completing necessary forms and presenting a valid ID. The prize will need to be claimed on dates outlined by the sponsor, and any additional travel expenses or taxes incurred will be the winner's responsibility.
Further details and entry information can be found on the Bloomington Minnesota Travel & Tourism website.
